Task – Find Minimum and Maximum Element in an Array

Problem Statement Given an array arr[], the task is to find: The minimum element in the array The maximum element in the array Return both values in a list as: [min, max] Example 1 Input: arr[] = [1, 4, 3, 5, 8, 6] Output: [1, 8] Explanation: Minimum element is 1 Maximum element is 8 Example 2 Input: arr[] = [12, 3, 15, 7, 9] Output: [3, 15] Explanation: Minimum element is 3 Maximum element is 15 Constraints 1 ≤ arr.size() ≤ 10^5 1 ≤ arr[i] ≤ 10^9 Logical Approach To solve this problem: Assume the first element is both minimum and maximum. Traverse the array from index 1 to end. For each element: If it is smaller than current minimum → update minimum If it is greater than current maximum → update maximum Return both values. This approach ensures we check each element only once. Time Complexity: O(n) Space Complexity: O(1) SOLUTION: class Solution: def getMinMax(self, arr): minimum = arr[0] maximum = arr[0] for i in range(1, len(arr)): if arr[i] < minimum: minimum = arr[i] if arr[i]